3x^2-12x+31=2x^2-5

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Solution for 3x^2-12x+31=2x^2-5 equation: 



3x^2-12x+31=2x^2-5

We move all terms to the left:

3x^2-12x+31-(2x^2-5)=0

We get rid of parentheses

3x^2-2x^2-12x+5+31=0

We add all the numbers together, and all the variables

x^2-12x+36=0

a = 1; b = -12; c = +36;
Δ = b2-4ac
Δ = -122-4·1·36
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{12}{2}=6$

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